MCQ
Consider the following reaction

(image) $\frac{{{H_2}}}{{pd - BaS{O_4}}}\,'A'$

The product $'A'$ is

  • A
    $C_6H_5COCH_3$
  • B
     $C_6H_5Cl$
  • $C_6H_5CHO$
  • D
    $C_6H_5OH$

Answer

Correct option: C.
$C_6H_5CHO$
c
It is rosenmund's reaction, which is used in partial reduction of acidchlorides into aldehydes

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$\begin{array}{*{20}{c}}
  {C{H_3}\,\,\,\,\,\,\,O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
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