MCQ
Consider the following standard electrode potentials ($E^o$ in volts) in aqueous solution

Element $M^{3+}/ M$ $M^+/M$
$Al$ $-1.66$ $+0.55$
$Tl$ $+1.26$ $-0.34$

Based on these data, which of the following statements is correct ?

  • A
    $Tl^+$ is more stable than $Al^{3+}$
  • B
    $Al^+$ is more stable than $Al^{3+}$
  • $Tl^+$ is more stable than $Al^+$
  • D
    $Tl^{3+}$ is more stable than $Al^{3+}$

Answer

Correct option: C.
$Tl^+$ is more stable than $Al^+$
c
$(i)\,\mathop {A{l^{3 + }}}\limits_{Most\,\,stable} \,\xrightarrow{{{E^o}\, = \, - \,1.66}}Al\,\xleftarrow{{{E^o}\, = \, + \,0.55}}\mathop {A{l^ + }}\limits_{Less\,\,stable} $

$(ii)\mathop {T{l^{3 + }}}\limits_{Less\,\,stable} \,\xrightarrow{{{E^o}\, = \, -  + 1.26}}Tl\,\xleftarrow{{{E^o}\, = \, - 0.34}}\mathop {T{l^ + }}\limits_{Most\,\,\,stable} $

$Tl^+$ has negative electrode potential $(E^o = - 0.34)$ means, it does not prefer to convert into $Tl$ but reverse must be preferred that's why it is more stable than $Tl^{3+}$ $(E^o\,=\,+\,1.26)$ In $Al$, $Al^{3+}$ is more stable $E^o=\,-\,1.66$ than $Al^+$  $(E^o\,=\,+0.55)$ and also from $Tl^+$ due to more negative value of $E^o$. Therefore, by comparison it confirms that $Tl^+$ is more stable than $Al^+$.

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