MCQ
Consider the function $f:(-\infty, \infty) \rightarrow(-\infty, \infty)$ defined by $f(x)=\frac{x^2-a x+1}{x^2+a x+1}, 0 < a < 2 .$

$1.$ Which of the following is true?

$(A)$ $(2+a)^2 f^{\prime \prime}(1)+(2-a)^2 f^{\prime \prime}(-1)=0$

$(B)$ $(2-a)^2 f^{\prime}(1)-(2+a)^2 f^{\prime \prime}(-1)=0$

$(C)$ $f^{\prime}(1) f^{\prime}(-1)=(2-a)^2$

$(D)$ $f^{\prime}(1) f^{\prime}(-1)=-(2+a)^2$

$2.$ Which of the following is true?

$(A)$ $f(x)$ is decreasing on $(-1,1)$ and has a local minimum at $x=1$

$(B)$ $f(x)$ is increasing on $(-1,1)$ and has a local maximum at $x=1$

$(C)$ $f(x)$ is increasing on $(-1,1)$ but has neither a local maximum nor a local minimum at $x=1$

$(D)$ $f(x)$ is decreasing on $(-1,1)$ but has neither a local maximum nor a local minimum at $x=1$

$3.$ Let $g(x)=\int_0^{e^x} \frac{f^{\prime}(t)}{1+t^2} d t$ which of the following is true?

$(A)$ $g^{\prime}(x)$ is positive on $(-\infty, 0)$ and negative on $(0, \infty)$

$(B)$ $g^{\prime}(x)$ is negative on $(-\infty, 0)$ and positive on $(0, \infty)$

$(C)$ $\mathrm{g}^{\prime}(\mathrm{x})$ changes sign on both $(-\infty, 0)$ and $(0, \infty)$

$(D)$ $g^{\prime}(x)$ does not change sign on $(-\infty, \infty)$

Give the answer question $1,2$ and $3.$

  • $(A,A,B)$
  • B
    $(C,D,B)$
  • C
    $(A,D,C)$
  • D
    $(C,B,B)$

Answer

Correct option: A.
$(A,A,B)$
a
$1.$   $ f^{\prime \prime}(x)=\frac{4 a x\left(x^2+a x+1\right)^2-4 a x\left(x^2-1\right)(2 x+a)\left(x^2+a x+1\right)}{\left(x^2+a x+1\right)^4} $

$ f^{\prime \prime}(1)=\frac{4 a}{(2+a)^2} \quad f^{\prime \prime}(-1)=\frac{-4 a}{(2-a)^2} $

$ (2+a)^2 f^{\prime \prime}(1)+(2-a)^2 f^{\prime \prime}(-1)=0$

$2.$  $f^{\prime}(x)=\frac{2 a\left(x^2-1\right)}{\left(x^2+a x+1\right)^2}$

Decreasing $(-1,1)$ and minima at $\mathrm{x}=1$

$3.$ $g^{\prime}(x)=\frac{f^{\prime}\left(e^x\right) e^x}{1+e^{2 x}}$

Hence positive for $(0, \infty)$ and negative for $(-\infty, 0)$.

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