MCQ
Consider the function$f (x) = x\, cos x - sin x$, then identify the statement which is correct .
- A$f$ is neither odd nor even
- ✓$f$ is monotonic decreasing at $x = 0$
- C$f$ has a maxima at $x = \pi$
- D$f$ has a minima at $x = - \pi$
$\left. \begin{array}{l}f ' ({0^ - }) = ( - )( - )( - ) < 0\\f'\,({0^ + }) = ( - )( + )( + ) < 0\end{array} \right]$ no sign change
This also implies that $f$ is decreasing at $x = 0 ==>$$(B)$ is correct
$f''(x) = - (x cos x + sin x)$
$f'' (\pi ) = - (--\pi ) > 0$ minima at $x = \pi $
$f '' (- \pi ) = - (\pi ) < 0$ maxima at $x = \pi $]
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$\left( {x + 2{y^3}} \right)\frac{{dy}}{{dx}} - y = 0$ is
$STATEMENT -1$ : For each real $\mathrm{t}$, there exists a point $\mathrm{c}$ in $[\mathrm{t}, \mathrm{t}+\pi]$ such that $\mathrm{f}^{\prime}(\mathrm{c})=0$. because
$STATEMENT -2$: $f(t)=f(t+2 \pi)$ for each real $t$.