MCQ
Consider the junction diode as ideal. The value of current flowing through $AB$ is
  • $10^{-2}\;A$
  • B
    $10^{-1}\;A$
  • C
    $10^{-3}\;A$
  • D
    $0\;A$

Answer

Correct option: A.
$10^{-2}\;A$
a
Here, the $p-n$ junction diode is forwarc biased, hence it offers zero resistance

$\therefore {{I}_{AB}}=\frac{{{V}_{A}}-{{V}_{B}}}{{{R}_{AB}}}=$ $\frac{4\text{V}-(-6\text{V})}{1\text{k}\Omega }=$ $\frac{10}{1000}\text{A}={{10}^{-2}}\text{A}$

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