MCQ
Consider the objective function $Z = 40x + 50y$ The minimum number of constraints that are required to maximize $Z$ are :
  • A
    $4$
  • B
    $2$
  • $3$
  • D
    $1$

Answer

Correct option: C.
$3$
Since in the given function $Z = 40x + 50y,$ two variables are used.
So, the two constraints will be $\text{x}\geq0,\text{y}\geq0$ and the third one will be of the type
$\text{ax}+\text{by}\geq\text{c}.$
Hence, at least $3$ constraints are required.

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