MCQ
Considering the elements $\ce{F, Cl, O}$ and $N,$ the correct order of their chemical reactivity in terms of oxidizing property is :
- A$\ce{F > Cl > O > N}$
- B$\ce{F > O > Cl > N}$
- C$\ce{Cl > F > O > N}$
- D$\ce{O > F > N > Cl}$
✓
Answer
In a period, the non $-$ metallic character increases from left to right.
Thus, among $\ce{B, C, N} $ and $F,$ non $-$ metallic character decreases in the order :
$\ce{F > N > C > B}$.
However, within a group, non $-$ metallic character decreases from top to bottom.
Thus, $C$ is more non $-$ metallic than $\ce{Si}.$
Therefore, the correct sequence of decreasing non-metallic character is : $\ce{F > N > C > B > Si},$ i.e.,
Thus, among $\ce{B, C, N} $ and $F,$ non $-$ metallic character decreases in the order :
$\ce{F > N > C > B}$.
However, within a group, non $-$ metallic character decreases from top to bottom.
Thus, $C$ is more non $-$ metallic than $\ce{Si}.$
Therefore, the correct sequence of decreasing non-metallic character is : $\ce{F > N > C > B > Si},$ i.e.,
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