Question
Construct a ∆ ABC such that AB = 6 cm, BC = 4.5 cm and AC = 5.5 cm. Construct a circumcircle of this triangle.
✓
Answer
Steps of Construction :
(i) Draw a line segment $BC =4.5 cm$
(ii) With centre $B$ and radius $6 cm$, draw are arc
(iii) With centre $C$ and radius $5.5 cm$, draw another arc intersecting the first arc at $A$.
(iv) Join $A B$ and $A C$.
$\triangle ABC$ is the required triangle.
(v) Draw the perpendicular bisectors of $A B$ and $A C$. Which intersects each other at $O$.
(vi) Join $O B, O C$ and $O A$.
(vii) With centre $O$ and radius $OA$, draw a circle which passes through A, B and C.
This is the required circumcircle of $\triangle A B C$.
(i) Draw a line segment $BC =4.5 cm$
(ii) With centre $B$ and radius $6 cm$, draw are arc
(iii) With centre $C$ and radius $5.5 cm$, draw another arc intersecting the first arc at $A$.
(iv) Join $A B$ and $A C$.
$\triangle ABC$ is the required triangle.
(v) Draw the perpendicular bisectors of $A B$ and $A C$. Which intersects each other at $O$.
(vi) Join $O B, O C$ and $O A$.
(vii) With centre $O$ and radius $OA$, draw a circle which passes through A, B and C.
This is the required circumcircle of $\triangle A B C$.
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