Question
Construct a galvanic cell from the electrodes $Co ^{3+} \mid Co$ and $Mn ^{2+} \mid Mn . E _{ C 0}^0=1.82 V$, $E _{ Mn }^0=-1.18 V$. Calculate $E _{\text {cell }}^0$

Answer

Given : $E_{ Co ^3 / Co }^0=1.82 V ; E_{ Mn ^{2+} / Mn }^0=-1.18 V$ $E_{ cell }^0=$ ?
The galvanic cell is,
$ Mn _{( s )}\left| M ^{2+}(1 M ) \| Co ^{3+}(1 M )\right| Co _{( s )}$
$ E_{ cell }^0  =E_{ Co ^{3+} / Co }^0-E_{ Mn ^{2+} / Mn }^0$
$ =1.82-(-1.18)$
$ =3.0 V$
Ans. $E_{\text {cell }}^0=3.0 V$

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