Question
Construct a kite $ABCD$ in which $AB = 4\ cm, BC = 4.9\ cm$ and $AC = 7.2\ cm$.
✓
Answer
Steps of construction:
Step $I$: Draw $AC = 7.2\ cm$.
Step $II$: With $A$ as the centre and radius $4\ cm$, draw arcs on both sides of the line segment $AC$.
Step $III$: With $C$ as the centre and radius $4.9\ cm$, draw arcs on both sides of $AC$ intersecting the previous arcs of step $II$ at $B$ and $D$.
Step $IV$: Join $BA, DA, BC$ and $CD$. Thus, the quadrilateral $ABCD$ so obtained is the required kite.
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S.No
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Column $I$
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S.No
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Column II
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$1.$
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x and y vary inversely to each other
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$A.$
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$\frac{\text{x}}{\text{y}}=\text{constant}$
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$2.$
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Mathematical representation of inverse
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$B.$
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$y$ will increase in proportion
|
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$3.$
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Mathematical representation of
direct variation of quantities
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$C.$
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$xy$ = Constant
|
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$4.$
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When $x = 5, y = 2.5$ and when
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$D.$
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$\text{p} \propto\frac{1}{\text{q}}$
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$5.$
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When $x = 10 , y = 5$ and when
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$E.$
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$y$ will decrease in proportion
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$6.$
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x and y vary directly with each other
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$F.$
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$x$ and $y$ are directly proportional
|
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$7.$
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If x and y vary inversely then on decreasing x
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$G.$
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$\text{m }\alpha \text{ n}$
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$8.$
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If x and y vary directly then on decreasing
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$H.$
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$x$ and $y$ vary inversely
|
|
|
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$I.$
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$\text{p } \alpha \text{ q}$
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$J.$
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$\text{m }\alpha \frac{1}{\text{n}}$
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Elements
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Mass of atom $(kg)$
|
|
Titanium
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$7.95 \times 10^{-26}$ |
|
Lead
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$3.44 \times 10^{-25}$ |
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Silver
|
$1.79 \times 10^{-25}$ |
|
Lithium
|
$1.15 \times 10^{-26}$ |
|
Hydrogen
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$1.674 \times 10^{-27}$ |
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