Question
Construct a parallelogram $ABCD$ in which $BC = 5\ cm,$ $\angle\text{BCD}=120^\circ$ and $CD = 4.8\ cm.$
✓
Answer
Steps of construction:
Step 1: Draw $BC = 5\ cm.$
Step 2: Make an $\angle\text{BCD}=120^\circ.$
Step 2: With $C$ as centre draw an arc of $4.8\ cm,$ name that point as $D.$
Step 3: With $D$ as centre draw an arc $5\ cm, $ name that point as $A.$
Step 4: With $B$ as centre draw another arc $4.8\ cm$ cutting the previous arc at $A$.
Step 5: Join $AD$ and $AB.$
Then, $ABCD$ is a required parallelogram.
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