Question
Construct a parallelogram ABCD, in which diagonal AC = 3.8cm, diagonal BD = 4.6cm and the angle between AC and BD is 60°.
✓
Answer
We know that the diagonals of a parallelogram bisect each other.
Steps of construction:
Step 1: Draw AC = 3.8cm. Step 2: Bisect AC at O. Step 3: Make $\angle\text{COX}=60^\circ$ Produce XO to Y.Step 4:
$\text{OB}=\frac{1}{2}(4.6)\text{cm}$ $\text{OB}=2.3\text{cm}$ and $\text{OD}=\frac{1}{2}(4.6)\text{cm}$ $\text{OD}=2.3\text{cm}$ Step 5: Join AB, BC, CD and AD. Thus, ABCD is the required parallelogram.
Steps of construction:
Step 1: Draw AC = 3.8cm. Step 2: Bisect AC at O. Step 3: Make $\angle\text{COX}=60^\circ$ Produce XO to Y.Step 4:
$\text{OB}=\frac{1}{2}(4.6)\text{cm}$ $\text{OB}=2.3\text{cm}$ and $\text{OD}=\frac{1}{2}(4.6)\text{cm}$ $\text{OD}=2.3\text{cm}$ Step 5: Join AB, BC, CD and AD. Thus, ABCD is the required parallelogram.
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