Question
Construct a parallelogram $\text{ABCD}$, when:Diagonal $AC = 6.4 \ cm,$ diagonals $BD = 8.2 \ cm$ and angle between the diagonals$ = 60^\circ .$
✓
Answer
Steps:
$1.$ Draw $AC =6.4 cm$.
$2.$ Draw line $BOD$ such that $\angle DOC =60^{\circ}$ and $OB = OD =\frac{1}{2} BD =\frac{1}{2} \times 8.2=4.1 cm$
$3.$ Join $AB, BC, CD$, and $DA$.
$\text{ABCD}$ is the required parallelogram.
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