Question
Construct a parallelogram PQRS in which QR = 6cm, PQ = 4cm and $\angle\text{PQR}=60^\circ.$
✓
Answer
Steps of construction:Step 1: Draw PQ = 4cm.
Step 2: Make $\angle\text{PQR}=60^\circ.$
Step 2: With Q as the centre, draw an arc of 6cm and name that point as R.
Step 3: With R as the centre, draw an arc of 4cm and name that point as S.
Step 4: Join SR and PS.
Then, PQRS is the required parallelogram.
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