Question
Construct a quadrilateral $\text{ABCD}$ in which ; $\angle A = 120^\circ , \angle B = 60^\circ , AB = 4 \ cm, BC = 4.5 \ cm$ and $CD = 5 \ cm.$
✓
Answer
The rough figure is as follow :
The Actual figure is constructed as follow
Steps :
The Actual figure is constructed as follow
Steps :
- Draw $AB = 4 \ cm$.
- At $A$, draw $\angle PAB = 120^\circ$ .
- At $B$, draw $\angle QBA = 60^\circ$ .
- From $BQ$, cut $BC = 4.5 \ cm$.
- From $C$, draw an arc of radius $5 \ cm$ which meets $AP$ at $D$.
- Join $CD$.
Thus $\text{ABCD}$ is the required quadrilateral.
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