Question
Construct a quadrilateral $ABCD$ in which $AB = 2.9\ cm, BC = 3.2\ cm, CD = 2.7\ cm, DA = 3.4\ cm$ and $\angle\text{A}=70^\circ.$

Answer



Steps of construction:
Step 1: Draw $AB = 2.9\ cm.$
Step 2: Make $\angle\text{A}=70^\circ$
Step 3: With $A$ as the centre, draw an arc of $3.4\ cm.$ Name that point as $D.$​​​​​​​
Step 4: With $D$ as the centre, draw an arc of $2.7\ cm.$​​​​​​​
Step 5: With $B$ as the centre, draw an arc of $3.2\ cm,$ cutting the previous arc at $C.$​​​​​​​
Step 6: Join $CD$ and $BC.$
Then, $ABCD$ is the required quadrilateral.

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