Gujarat BoardEnglish MediumSTD 8MATHSPractical Geometry (Constructions)5 Marks
Question
Construct a quadrilateral $ABCD$ in which $AB = 4.4\ cm$$, BC = 4\ cm, CD = 6.4\ cm, DA = 3.8\ cm$ and $BD = 6.6\ cm$.
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Answer
First, we draw a rough sketch of the quadrilateral $ABCD$ and write down its dimensions along the sides.
We may divide the quadrilateral into two constructible triangles $ABD$ and $BCD$. Steps of Construction: Step I: Draw $BD = 6.6\ cm$ Step II: With $B$ as the centre and radius $BC = 4\ cm$, draw an arc. Step III: With $D$ as the centre and radius $6.4\ cm$, draw an are to intersect th are drawn in Step $II$ at $C$. Step IV: With $B$ as the centre and radius $4.4\ cm$, draw an arc on the side $BD$ opposite to that of $C$. Step V: With $D$ as the centre and radius $3.8\ cm$, draw an arc to intersect the arc drawn in Step $IV$ at $A$. Step VI: Join $BA, DA, BC$ and $CD$ The quadrilateral $ABCD$ so obtained is the required quadrilateral.
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