Question
Construct a quadrilateral $\text{ABCD},$ when$:AB = 6.3 \ cm, BC = CD = 4.2 \ cm$ and $\angle ABC = \angle BCD = 90^\circ .$
✓
Answer
Steps :
$1.$ draw $A B=6.3 \ cm$.
$2.$ Draw $B P$ such that $\angle A B P=90^{\circ}$.
$3.$ With $B$ as a center and radii, $4.2 \ cm$ draw an arc $A P$ at $C$.
$4.$ With $C$ as a center draw a line $CD$ with radii $4.2 \ cm$. draw a line such that $\angle BCD=90^{\circ}$.
$5.$ Now join $AD.$
$\text{ABCD}$ is the required quadrilateral.
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