Question
Construct a quadrilateral $PQRS$, in which $PQ = 4\ cm, QR = 5\ cm$, $\angle\text{P}=50^\circ,\angle\text{P}=110^\circ$ and $\angle\text{R}=70^\circ.$
✓
Answer
Steps of construction:
Step $I$: Draw $PQ = 4\ cm$.
Step $II$: Construct $\angle\text{XPQ}=50^\circ$ at $P$ and $\angle\text{PQY}=110^\circ$ at $Q$.
Step $III$: With $Q$ as the centre and radius $5\ cm$, cut off $QR = 5\ cm$.
Step $IV$: At $R$, draw $\angle\text{QRZ}=70^\circ$ such that it meets $PX$ at $S$.
The quadrilateral so obtained is the required quadrilateral.
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