Question
Construct a rhombus $\text{ABCD},$ when:Diagonal $AC = 6.3 \ cm$ and diagonal $BD = 5.8 \ cm.$
✓
Answer
Steps:
$1.$ Draw $AC =6.3 \ cm$.
$2.$ Draw perpendicular bisector to $AC$ which cuts $AC$ at $O$.
$3.$ From this perpendicular cut $OD$ and $O$B such that,
$OD = OB =\frac{1}{2} BD =\frac{1}{2} \times 5.8=2.9 \ cm$.
$4.$ Join $AB , BC , CD$, and $DA$.
$\text{ABCD}$ is the required rhombus.
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