Question
Construct a rhombus the lengths of whose diagonals are 6cm and 8cm.
✓
Answer
We know that the diagonals of a rhombus bisect each other.
Steps of construction: Step 1: Draw AC = 6cm. Step 2: Draw a perpendicular bisector (XY) of AC, which bisects AC at O. Step 3: $\text{OB}=\frac{1}{2}(8)\text{cm}$ $\text{OB}=4\text{cm}$ and $\text{OD}=\frac{1}{2}(8)\text{cm}$ Draw an arc of length 4cm on OX and name that point as B. Draw an arc of length 4cm on OY and name that point as D. Step 4: Join AB, BC, CD and AD. Thus, ABCD is the required rhombus, as shown in the figure.
Steps of construction: Step 1: Draw AC = 6cm. Step 2: Draw a perpendicular bisector (XY) of AC, which bisects AC at O. Step 3: $\text{OB}=\frac{1}{2}(8)\text{cm}$ $\text{OB}=4\text{cm}$ and $\text{OD}=\frac{1}{2}(8)\text{cm}$ Draw an arc of length 4cm on OX and name that point as B. Draw an arc of length 4cm on OY and name that point as D. Step 4: Join AB, BC, CD and AD. Thus, ABCD is the required rhombus, as shown in the figure.
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