Question
Construct a right triangle $ABC$ in which $AB = 5.8\ cm, BC = 4.5\ cm$ and $\angle\text{C}=90^\circ.$
✓
Answer
Steps of construction:
Step I: Draw a line segment $BC = 4.5\ cm.$
Step II: Draw $\angle\text{BCX}$ of measure $90^\circ .$
Step III: With centre $B$ and radius $AB = 5.8\ cm$, draw an arc of the circle to intersect ray $BX$ at $A$.
Step IV: Join $AB$ to obtain the desired triangle $ABC$.
Step V: $ABC$ is the required triangle.
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