Question
Construct a right triangle, right angled at $C$ in which $AB = 5.2\ cm$ and $BC= 4.6\ cm.$

Answer


Steps of construction:
Step I: Draw a line segment $BC = 4.6\ cm.$
Step II: Draw $\angle\text{BCX}$ of measure $90^\circ $.
Step III: With centre $B$ and radius $AB = 5.2\ cm$, draw an arc of the circle to intersect ray $CX$ at $A$.
Step IV: Join $AB$ to obtain the desired triangle $ABC$.
Step V: $ABC$ is the required triangle.

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