Question
Construct a $\triangle ABC$ in which $BC = 5\ cm$, $\angle\text{B}=60^\circ$ and $AC + AB = 7.5\ cm.$
✓
Answer
$1.$ Draw the base $BC = 5\ cm.$
$2.$ At the point $B$ make an $\angle\text{XBC}=60^\circ$
$3.$ Cut a line segment $BD$ equal to $AB + AC = 7.5\ cm$ from the ray $BX.$
$4.$ Join $DC.$
$5.$ Make an $\angle\text{DCY}=\angle\text{BDC}$
$6.$ Let $CY$ intersect $BX$ at $A.$
Then, $\triangle\text{ABC}$ is the required triangle.
$2.$ At the point $B$ make an $\angle\text{XBC}=60^\circ$
$3.$ Cut a line segment $BD$ equal to $AB + AC = 7.5\ cm$ from the ray $BX.$
$4.$ Join $DC.$
$5.$ Make an $\angle\text{DCY}=\angle\text{BDC}$
$6.$ Let $CY$ intersect $BX$ at $A.$
Then, $\triangle\text{ABC}$ is the required triangle.
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