Question
Construct a triangle similar to a given $\angle\text{ABC}$ such that each of its sides is rd of the corresponding sides of $\triangle\text{ABC}.$ It is given that BC = 6cm, $\angle\text{B} = 50^\circ$ and $\angle\text{C} = 60^\circ.$
✓
Answer
Steps of construction:
i. Draw a line segment $B C=6 cm$.
ii. Draw a ray $B X$ making an angle of $50^{\circ}$ and $C Y$ making $60^{\circ}$ with $B C$ which intersect each other at $A$. Then $A B C$ is the triangle.
iii. From $B$, draw another ray $B Z$ making an acute angle below $B C$ and intersect 3 equal parts making $B_1=B_1 B_2=$ $B _2 B_2$.
iv. Join $B _3 C$.
v. From $B _2$, draw $B _2 C ^{\prime}$ parallel to $B _3 C$ and $C ^{\prime} A ^{\prime}$ parallel to CA .
Then $\Delta\text{A}’\text{BC}’$ is the required triangle.
i. Draw a line segment $B C=6 cm$.
ii. Draw a ray $B X$ making an angle of $50^{\circ}$ and $C Y$ making $60^{\circ}$ with $B C$ which intersect each other at $A$. Then $A B C$ is the triangle.
iii. From $B$, draw another ray $B Z$ making an acute angle below $B C$ and intersect 3 equal parts making $B_1=B_1 B_2=$ $B _2 B_2$.
iv. Join $B _3 C$.
v. From $B _2$, draw $B _2 C ^{\prime}$ parallel to $B _3 C$ and $C ^{\prime} A ^{\prime}$ parallel to CA .
Then $\Delta\text{A}’\text{BC}’$ is the required triangle.
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