Question
Construct a triangle using the following data: $DE + EF = 10.3 \ cm, EF = 6.4 \ cm$ and $\angle E = 75^\circ $

Answer

$DE + EF = 10.3 \ cm, EF = 6.4 \ cm$ and $\angle E = 75^\circ $

Steps of construction:
$1$. Draw a line segment $EF = 6.4 \ cm.$
$2.$ With $E$ as centre, construct $\angle SEF = 75^\circ $
$3.$ Cut $ET = 10.3 \ cm$ on $ES.$
$4$. Join $TF.$
$5$. Draw perpendicular bisector of $TF$ which cuts $ET$ at $D.$
$6$. Join $DF.$
Thus $\text{DEF}$ is the required triangle.

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