Question
Construct a triangle using the following data: $PQ + PR = 10.6 \ cm, QR = 4.8 \ cm$ and $\angle R = 45^\circ $
✓
Answer
$PQ + PR = 10.6 \ cm, QR = 4.8 \ cm$ and $\angle R = 45^\circ $
Steps of construction:
$1.$ Draw a line segment $QR = 4.8 \ cm$
$2.$ With $Q$ as centre, construct $\angle SQR = 45^\circ $
$3.$ Cut $QT = 10.6 \ cm$ on $QS.$
$4$. Join $TR.$
$5$. Draw perpendicular bisector of $TR$ which cuts $QT$ at $P.$
$6.$ Join $PR.$
Thus $\text{PQR}$ is the required triangle.
Steps of construction:
$1.$ Draw a line segment $QR = 4.8 \ cm$
$2.$ With $Q$ as centre, construct $\angle SQR = 45^\circ $
$3.$ Cut $QT = 10.6 \ cm$ on $QS.$
$4$. Join $TR.$
$5$. Draw perpendicular bisector of $TR$ which cuts $QT$ at $P.$
$6.$ Join $PR.$
Thus $\text{PQR}$ is the required triangle.
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