Question
Construct a triangle with its sides $4 cm, 5 cm$ and 6 cm . Then construct a triangle similar to it whose sides are $\frac{2}{3}$ of the corresponding sides of the first triangle.
✓
Answer
In $\triangle ABC$, $
\begin{aligned}
AB & =4 cm \\
BC & =6 cm \\
AC & =5 cm \\
\text { Ratio } & =\frac{2}{3}
\end{aligned}
$
$A ^{\prime} BC ^{\prime}$ is the required triangle.
\begin{aligned}
AB & =4 cm \\
BC & =6 cm \\
AC & =5 cm \\
\text { Ratio } & =\frac{2}{3}
\end{aligned}
$
$A ^{\prime} BC ^{\prime}$ is the required triangle.
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