Question
Construct a triangle with sides $5 cm, 5.5 cm$ and 6.5 cm . Now construct another triangle, whose sides are $\frac{3}{5}$ times the corresponding sides of the given triangle.
✓
Answer
Step 1: Construct a triangle $P Q R$ such that $Q R=5.5 cm$. Considering $Q$ as center, mark an arc of length 5 cm and considering $R$ as center, mark an arc of length 6.5 cm . The point of intersection of ares is called $P$.
Step 2: Draw a line $Q M$ such that it makes an acute angle with $Q R$.
Step 3: Draw 5 points $Q_1, Q_2, Q_3, Q_4$ and $Q_5$ on equal distance from each other on $Q M$ and then join the fifth mark to point $R$.
Step 4: Draw a line $Q_3 R$ ' parallel to $Q_5 R$ from $Q_3$
Step 5: Draw a line $R$ ' $P$ ' parallel to $R P$
Step 6: $P ^{\prime} Q R$ ' is the required triangle.$A ^{\prime} BC ^{\prime}$ is the required triangle.
Step 2: Draw a line $Q M$ such that it makes an acute angle with $Q R$.
Step 3: Draw 5 points $Q_1, Q_2, Q_3, Q_4$ and $Q_5$ on equal distance from each other on $Q M$ and then join the fifth mark to point $R$.
Step 4: Draw a line $Q_3 R$ ' parallel to $Q_5 R$ from $Q_3$
Step 5: Draw a line $R$ ' $P$ ' parallel to $R P$
Step 6: $P ^{\prime} Q R$ ' is the required triangle.$A ^{\prime} BC ^{\prime}$ is the required triangle.
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