Question
Construct a triangle with sides 5cm, 5.5cm and 6.5cm. Now construct another triangle, whose sides are $\frac{3}{5}$ times the corresponding sides of the given triangle.

Answer

Steps of construction:
  1. Draw line segment BC = 5.5cm.
  2. With centre B and radius 5cm and with centre C and radius 6.5cm, draw arcs which intersect each other at A.
  3. Join BA and CA. $\triangle\text{ABC}$ is the given triangle.
  4. At B, draw a ray BX making an acute angle and cut off 5 equal parts from BX.
  5. Join C5 and draw 3D || 5C which meets BC at D.
From D, draw DE || CA which meets AB at E.$\therefore\triangle\text{EBD}$ is the required triangle.

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