Question
Construct a triangle with sides 5cm, 6cm and 7cm and then another triangle whose sides are $\frac{7}{5}$ of the corresponding sides of the first triangle.
✓
Answer
Steps of construction:
i. Draw a line segment $B C=5 cm$.
ii. With centre $B$ and radius 6 cm and with centre $C$ and radius 7 cm , draw arcs intersecting each other at $A$.
iii. Join $A B$ and $A C$. Then $A B C$ is the triangle.
iv. Draw a ray $B X$ making an acute angle with $B C$ and cut off 7 equal parts making $B B_1=B_1 B_2=B_2 B_3=B_3 B_4=$ $B _4 B_5= B _5 B_6= B _6 B_7$.
v. Join $B_5$ and $C$.
vi. From $B _7$, draw $B _7 C ^{\prime}$ parallel to $B _5 C$ and $C ^{\prime} A ^{\prime}$ parallel CA . Then $\triangle A ^{\prime} BC ^{\prime}$ is the required triangle.
i. Draw a line segment $B C=5 cm$.
ii. With centre $B$ and radius 6 cm and with centre $C$ and radius 7 cm , draw arcs intersecting each other at $A$.
iii. Join $A B$ and $A C$. Then $A B C$ is the triangle.
iv. Draw a ray $B X$ making an acute angle with $B C$ and cut off 7 equal parts making $B B_1=B_1 B_2=B_2 B_3=B_3 B_4=$ $B _4 B_5= B _5 B_6= B _6 B_7$.
v. Join $B_5$ and $C$.
vi. From $B _7$, draw $B _7 C ^{\prime}$ parallel to $B _5 C$ and $C ^{\prime} A ^{\prime}$ parallel CA . Then $\triangle A ^{\prime} BC ^{\prime}$ is the required triangle.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Solve the following quadratic equation:
$2^{2x} - 3.2^{(x+2)} + 32= 0$
→$2^{2x} - 3.2^{(x+2)} + 32= 0$
The angle of elevation of the top of building from the foot of a tower is 30°. The angle of elevation of the top of the tower from the foot of the building is 60°. If the tower is 60°. If the tower is 60m high, Find the height of the building.
In the given figure, D is the midpoint of side BC and $\text{AE}\perp\text{BC}.$ If BC = a, AC = b, AB = c, ED = x, AD = p and AE = h, prove that.
$\text{b}^2=\text{p}^2+\text{ax}+\frac{\text{a}^2}{4}$
→$\text{b}^2=\text{p}^2+\text{ax}+\frac{\text{a}^2}{4}$
Prove the following trigonometric identities.
$(\sec\text{A}-\text{cosec A})(1+\tan\text{A}+\cot\text{A})=\tan\text{A}\sec\text{A}-\cot\text{A}\text{ cosec A}$
→$(\sec\text{A}-\text{cosec A})(1+\tan\text{A}+\cot\text{A})=\tan\text{A}\sec\text{A}-\cot\text{A}\text{ cosec A}$
Two cones with same base radius 8cm and height 15cm are joined together along their bases. Find the surface area of the shape so formed.
Draw the less than type ogive for this data and use it to find the median weight.
If k, (2k - 1) and (2k + 1) are the three successive term of an AP, find the value of k.
Construct a triangle similar to a given $\triangle\text{XYZ}$ with its sides equal to $\Big(\frac{3}{4}\Big)^\text{th}$ of the corresponding sides of $\triangle\text{XYZ}$ Write the steps of construction.
→Find the area of the shaded region in the given figure, where a circular arc of radius 6cm has been drawn with vertex of an equilateral triangle of side 12cm as centre and a sector of circle of radius 6cm with centre B is made. $\big[\text{Use }\sqrt{3}=1.73\text{ and }\pi=3.14\big]$
→The angle of elevation of the top of a building from the foot of the tower is $30^{\circ}$ and the angle of elevation of the top of the tower from the foot of the building is $60^{\circ}$. If the tower is 60 m high, find the height of the building.
→