Question
Construct a triangle with sides 5cm, 6cm and 7cm and then another triangle whose sides are $\frac75$ of the corresponding sides of first triangle.

Answer


Steps of Construction:
Step 1. Draw a line segment BC = 4cm.
Step 2. With B as centre, draw an angle of $90^o.$​​​​​​​
Step 3. With B as centre and radius equal to 3cm, cut an arc at the right angle and name it A.
Step 4. Join AB and AC.
Thus, $\triangle\text{ABC}$ is obtained .
Step 5. Extend BC to D, such that $\text{BD}=\frac75\text{BC}=\frac75(4)\text{cm}=5.6\text{cm}.$
Step 6. Draw DE || CA, cutting AB produced to E.

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