Question
Construct a triangle with sides $5\ cm, 6\ cm$ and $7\ cm$ and then another triangle whose sides are $\frac75$ of the corresponding sides of first triangle.
✓
Answer
Steps of Construction:
Step 1. Draw a line segment $BC = 4\ cm.$
Step 2. With $B$ as centre, draw an angle of $90^\circ.$
Step 3. With $B$ as centre and radius equal to $3cm$, cut an arc at the right angle and name it $A.$
Step 4. Join $AB$ and $AC.$
Thus, $\triangle\text{ABC}$ is obtained .
Step 5. Extend $BC$ to $D$, such that $\text{BD}=\frac75\text{BC}=\frac75(4)\text{cm}=5.6\text{cm}.$
Step 6. Draw $DE || CA,$ cutting AB produced to $E.$
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