Question
Construct a $\triangle\text{ABC}$ in which AB = 3.8cm, $\angle\text{A}=60^\circ$ and AC = 5cm.
✓
Answer
Steps for construction: Step I: Draw AB of length 3.8cm. Step II: Draw $\angle\text{BAZ}=60^\circ$. Step III: With the centre as A, cut ray AZ at 5cm at C. Step IV: Join BC. Then, ABC is the required triangle.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Calculate the area of the quadrilateral ABCD as shown in Figure, given that BD = 42cm, AC = 28cm, OD = 12cm and $\text{AC}\bot\text{BO}.$
→In the given figure, two straight line PQ and RS intersect at a O. If $\angle\text{POS} = 114^\circ, $ find the measure of each of the angles:
→
- $\angle\text{POR}$
- $\angle\text{ROQ}$
- $\angle\text{QOS}$
Simplify:
$\Big(-5\times\frac{2}{15}\Big)-\Big(-6\times\frac{2}{9}\Big)$
→$\Big(-5\times\frac{2}{15}\Big)-\Big(-6\times\frac{2}{9}\Big)$
A man goes 3km due north and then 4km due east. How far is he away from his initial position?
$\text{m}-\frac{\text{m}-1}{2}=1-\frac{\text{m}-2}{3}$
→ABCD is quadrilateral.
Prove that (AB + BC + CD + DA) > (AC + BD)
Prove that (AB + BC + CD + DA) > (AC + BD)
Two poles, 18m and 13m high, stand upright in a playground. If their feet are 12m apart, find the distance between their tops.
Find the HCF and LCM of the numbers given below. Verify that their product is equal to the product of the given numbers : 18, 63
Heights of 25 children (in cm) in a school are as given below:
168, 165, 163, 160, 163, 161, 162, 164, 163, 162, 164, 163, 160, 163, 163, 164, 163, 160, 165, 163, 162
What is the mode of heights?
Also, find the mean and median.
168, 165, 163, 160, 163, 161, 162, 164, 163, 162, 164, 163, 160, 163, 163, 164, 163, 160, 165, 163, 162
What is the mode of heights?
Also, find the mean and median.
Simplify:
$\left(3 x^2+5 x-7\right)(x-1)-\left(x^2-3 x+3\right)(x+4)$
→$\left(3 x^2+5 x-7\right)(x-1)-\left(x^2-3 x+3\right)(x+4)$