Question
Construct a $\triangle\text{ABC}$ in which $AB = AC = 4.8\ cm$ and $BC = 5.3\ cm$. Measure $\angle\text{B}$ and $\angle\text{C}$. Draw $\text{AD}\bot\text{BC}$.

Answer

Steps for construction:
Step I: Draw $BC = 5.3cm$
Step II: Draw an arc of radius $4.8cm$ from the centre, $B.$​​​​​​​
Step III: Draw another arc of radius $4.8cm$ from the centre, $C.$​​​​​​​
Step IV: Both of these arcs intersect at $A$.
Step V: Join $AB$ and $AC.$​​​​​​​
Step VI: With $A$ as the centre and any radius, draw an arc cutting $BC$ at $M$ and $N.$​​​​​​​
Step VII: With $M$ as the centre and the radius more than half of $MN$, draw an arc.
Step VIII: With $N$ as the centre and the same radius, draw another arc cutting the previously drawn arc at $P$.
Step IX: Join $AP$, cutting $BC$ at $D$.Then, $\text{AD}\bot\text{BC}$

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