Question
Construct a $\triangle\text{ABC}$ in which AB = AC = 4.8cm and BC = 5.3cm. Measure $\angle\text{B}$ and $\angle\text{C}$. Draw $\text{AD}\bot\text{BC}$.
✓
Answer
Steps for construction:
Step I: Draw BC = 5.3cm
Step II: Draw an arc of radius 4.8cm from the centre, B.
Step III: Draw another arc of radius 4.8cm from the centre, C.
Step IV: Both of these arcs intersect at A.
Step V: Join AB and AC.
Step VI: With A as the centre and any radius, draw an arc cutting BC at M and N.
Step VII: With M as the centre and the radius more than half of MN, draw an arc.
Step VIII: With N as the centre and the same radius, draw another arc cutting the previously drawn arc at P.
Step IX: Join AP, cutting BC at D.Then, $\text{AD}\bot\text{BC}$
Step I: Draw BC = 5.3cm
Step II: Draw an arc of radius 4.8cm from the centre, B.
Step III: Draw another arc of radius 4.8cm from the centre, C.
Step IV: Both of these arcs intersect at A.
Step V: Join AB and AC.
Step VI: With A as the centre and any radius, draw an arc cutting BC at M and N.
Step VII: With M as the centre and the radius more than half of MN, draw an arc.
Step VIII: With N as the centre and the same radius, draw another arc cutting the previously drawn arc at P.
Step IX: Join AP, cutting BC at D.Then, $\text{AD}\bot\text{BC}$
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