Question
Construct a $\triangle\text{ABC}$ in which $AB = AC = 5.2\ cm$ and $\angle\text{A}=120^\circ.$ Draw $\text{AD}\bot\text{BC}.$
✓
Answer
Steps for construction:
Step I: Draw $AB = 5.2\ cm$
Step II: Draw $\angle\text{BAX}=120^\circ$
Step III: With $A$ as the centre, cut the ray $AX$ at $5.3\ cm$ at point $C.$
Step IV: Join $BC.$
Step V: $A$ as the centre and any radius, draw an arc cutting $BC$ at $M$ and $N.$
Step VI: With $M$ as the centre and the radius more than half of $MN,$ draw an arc.
Step VII: With $N$ as the centre and the same radius as before, draw another arc cutting the previously drawn arc at $P.$
Step VIII: Join $AP$ meeting $BC$ at $D.$
$\therefore\text{AD}=\text{BC}$
Step I: Draw $AB = 5.2\ cm$
Step II: Draw $\angle\text{BAX}=120^\circ$
Step III: With $A$ as the centre, cut the ray $AX$ at $5.3\ cm$ at point $C.$
Step IV: Join $BC.$
Step V: $A$ as the centre and any radius, draw an arc cutting $BC$ at $M$ and $N.$
Step VI: With $M$ as the centre and the radius more than half of $MN,$ draw an arc.
Step VII: With $N$ as the centre and the same radius as before, draw another arc cutting the previously drawn arc at $P.$
Step VIII: Join $AP$ meeting $BC$ at $D.$
$\therefore\text{AD}=\text{BC}$
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