Question
Construct a $\triangle\text{ABC}$ in which AB = AC = 5.2cm and $\angle\text{A}=120^\circ.$ Draw $\text{AD}\bot\text{BC}.$
✓
Answer
Steps for construction: Step I: Draw AB = 5.2cm Step II: Draw $\angle\text{BAX}=120^\circ$ Step III: With A as the centre, cut the ray AX at 5.3cm at point C. Step IV: Join BC. Step V: A as the centre and any radius, draw an arc cutting BC at M and N.Step VI: With M as the centre and the radius more than half of MN, draw an arc.
Step VII: With N as the centre and the same radius as before, draw another arc cutting the previously drawn arc at P.
Step VIII: Join AP meeting BC at D.
$\therefore\text{AD}=\text{BC}$
Step VII: With N as the centre and the same radius as before, draw another arc cutting the previously drawn arc at P.
Step VIII: Join AP meeting BC at D.
$\therefore\text{AD}=\text{BC}$
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