Question
Construct a $\triangle\text{ABC}$ in which $BC = 5.3cm$, $\angle\text{B}=60^\circ$ and $AB = 4.2cm$. Also, draw the perpendicular bisector of $AC.$
✓
Answer
Steps of construction:
Step 1: Draw $BC = 5.3cm$
Step 2: Construct $\angle\text{CBX}=60^\circ$
Step 3: With $B$ as the centre and radius $4.2cm$, cut the ray $BX$ at point $A.$
Step 4: Join $A$ and $C.$
Step 5: With $A$ as the centre and radius more than half of $AC$, draw an arc on either side of $AC.$
Step 6: With $C$ as the centre and the same radius, draw another arc cutting the previously drawn arc at $M$ and $N.$
Step 7: Join $M$ and $N.$
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