Question
Construct a $\triangle\text{ABC}$ in which BC = 7cm,$\angle\text{A}=45^\circ.$and $\angle\text{C}=75^\circ.$
✓
Answer
By angle sum property:$\angle\text{B}=180^\circ-\angle\text{A}-\angle\text{C}$
$=180^\circ-45^\circ-75^\circ$
$=60^\circ$
Steps for construction:
Step I: Draw AB = 7cm
Step II: Draw $\angle\text{BAX}=45^\circ$
Step III: Draw $\angle\text{ABY}=60^\circ$
Step IV: The ray AX an BY intersect at C. Then, ABC is the required triangle.
$=180^\circ-45^\circ-75^\circ$
$=60^\circ$
Steps for construction:
Step I: Draw AB = 7cm
Step II: Draw $\angle\text{BAX}=45^\circ$
Step III: Draw $\angle\text{ABY}=60^\circ$
Step IV: The ray AX an BY intersect at C. Then, ABC is the required triangle.
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