MCQ
Correct energy value order is :-
- A$ns\, np\, nd(n -1)f$
- B$ns\, np(n -1)d\, (n -2)f$
- C$ns\, np(n -1)d\, (n -1)f$
- ✓$ns(n -1)d\, n(n -1)f$
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Reason : $NaOH$ is strong alkali.
$\begin{array}{*{20}{c}}
{OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\
{\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\
{{C_6}{H_5} - CH - C{H_2} - C - C{H_3}}
\end{array}\mathop {\xrightarrow{{(i)\,NaOBr}}}\limits_{(ii)\,{H_2}O/{H^ + }\,(iii)\,\Delta } $ product
product will be :
