MCQ
Correct evaluation of $\int_{}^{} {\frac{x}{{(x - 2)(x - 1)}}\;dx} $ is

(where $p$  is an arbitrary constant)

  • ${\log _e}\frac{{{{(x - 2)}^2}}}{{(x - 1)}} + p$
  • B
    ${\log _e}\frac{{(x - 1)}}{{(x - 2)}} + p$
  • C
    $\frac{{x - 1}}{{x - 2}} + p$
  • D
    $2{\log _e}\left( {\frac{{x - 2}}{{x - 1}}} \right) + p$

Answer

Correct option: A.
${\log _e}\frac{{{{(x - 2)}^2}}}{{(x - 1)}} + p$
a
(a)$\int_{}^{} {\frac{x}{{(x - 2)(x - 1)}}\,dx} = - \int_{}^{} {\frac{1}{{x - 1}}\,dx + \int_{}^{} {\frac{2}{{x - 2}}\,dx} } $
$ = - {\log _e}(x - 1) + 2{\log _e}(x - 2) + c = {\log _e}\frac{{{{(x - 2)}^2}}}{{(x - 1)}} + p.$

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