Download App

5. Co-ordination chemistry — Chemistry STD 12 Science — Question

CBSE BoardEnglish MediumSTD 12 ScienceChemistry5. Co-ordination chemistry1 Mark
MCQ
Correct formula of potassium ferrocyanide is
  • ✓
    ${K_4}\left[ {Fe{{\left( {CN} \right)}_6}} \right]$
  • B
    ${K_2}\left[ {Fe{{\left( {CN} \right)}_6}} \right]{H_2}O$
  • C
    ${K_3}\left[ {Fe{{\left( {CN} \right)}_6}} \right]$
  • D
    None of these
✓

Answer

Correct option: A.
${K_4}\left[ {Fe{{\left( {CN} \right)}_6}} \right]$
a
(a)Follow $IUPAC$ rule.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from 5. Co-ordination chemistry→5. Co-ordination chemistry — all question types→Chemistry STD 12 Science question papers→CBSE Board STD 12 Science question papers→CBSE Board question paper generator→

Similar questions

The beta and alpha glucose have different specific rotations. When either is dissolved in water, their rotation changes until the same fixed value results. This is called
→
Polymer used to make gasket of pressure cooker is:
→
Which of the following is incorrect
→
Select the correct order of boiling point:
→
$\underbrace {\mathop {Hg{I_2}\,}\limits_{'X'} \xrightarrow[{Sublimation}]{\Delta }\,\mathop {Hg{I_2}}\limits_{'Y'} \xrightarrow{{Cooling}}\mathop {Hg{I_2}}\limits_{'Z'} }_{On\,\,rubbing}$
→
Consider the complex $[Co(NH_3)_4 CO_3]ClO_4$ , in which coordination  number, oxidation number and number of $d$-electrons on the metal are  respectively.
→
Consider following solutions

$(I)$  $1\, M$ glucose $(aq.)$

$(II)$ $1\, M$ sodium chloride $(aq.)$

$(III)$ $1\, M$ acetic acid in benzene

$(IV)$ $1\, M$ ammonium phosphate $(aq.)$

→
Set of $d-$ orbitals which is used by central metal during formation of $MnO^-_4$ ?
→
Which of the following alcohols will yield the corresponding alkyl chloride on reaction with concentrated $\text{HCl}$ at room temperature?
→
Identify the correct sequence for True and False

$(I)$ Only compounds with chiral centers can be optically active

$(II)$ Absence of elements of symmetry is the reason for a molecule's optical activity

$(II)$ All organic compounds contain carbon & hydrogen

$(IV)$ Different cannonical forms of a molecule represent the actual structures of a molecule which has resonace in it

→