MCQ
Correct increasing order of first ionistion potential is
- ✓$Na < Mg > Al < Si$
- B$Na < Mg < Al < Si$
- C$Na > Mg > Al > Si$
- D$Na < Mg < Al > Si$
Removal of an electron from stable, fully filled orbital requires more energy than removal of electron from partially filled orbital. Thus, ionisation enthalpy for $Mg$ is greater than ionisation enthalpy for $Al$. So, the correct order of first ionization enthalpies is: $Na \,<\, Mg\, >\, Al\, <\, Si$
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$(x)\begin{array}{*{20}{c}}
{O\,\,\,}\\
{||\,\,\,}\\
{C{H_3} - S - O - H}\\
{||\,\,\,\,}\\
{O\,\,\,\,}
\end{array}$
$\begin{array}{*{20}{c}}
{\,\,\,\,\,O}\\
{\,\,\,\,\,\,||}\\
{(y)\,\,\,C{H_3} - C - O - H}
\end{array}$
$(z)\,\, CH_3 -OH$
$Si_2H_6(g)\,\,+\,\,H_2(g)\,\,\to \,\, 2SiH_4(g),\,\,\Delta H\,\,=\,\,-\,11.7\,\,kJ/mol$
$SiH_4(g)\,\,\to \,\,SiH_2(g)\,\,+\,\,H_2(g),\,\, \Delta H\,\,=\,\,+239.7\,\,kJ/mol$
$\Delta H_f^o\,\,Si_2H_6(g)\,\,=\,\,80.3\,\,kJ/mol$
......$kJ/mol$