MCQ
Correct increasing order of first ionistion potential is
- ✓$Na < Mg > Al < Si$
- B$Na < Mg < Al < Si$
- C$Na > Mg > Al > Si$
- D$Na < Mg < Al > Si$
Removal of an electron from stable, fully filled orbital requires more energy than removal of electron from partially filled orbital. Thus, ionisation enthalpy for $Mg$ is greater than ionisation enthalpy for $Al$. So, the correct order of first ionization enthalpies is: $Na \,<\, Mg\, >\, Al\, <\, Si$
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(Atomic no. : $B = 5,S = 16,Ni = 28,Xe = 54$)

$2A{B_3}(g) \rightleftharpoons {A_2}(g) + 3{B_2}(g)$. At equilibrium, $2\, mol$ of $A_2$ are found to be present. The equilibrium constant of this reaction is