- ✓$BF_3 < BCl_3 < BBr_3 < BI_3$
- B$BF_3 > BCl_3 > BBr_3 > BI_3$
- C$BCl_3< BBr_3 < BI_3 < BF_3$
- D$BF_3 < BI_3 < BBr_3 < BCl_3$
(ii) Size of halides increase down the group, hence the ability of back bonding decreases making the molecule more acidic.
Hence, correct order of Lewis acid for boron-halides is $\mathrm{Bl}_{3}>\mathrm{BBr}_{3}>\mathrm{BCl}_{3}>\mathrm{BF}_{3}$
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$(A) \,2p_y +2p_y \to \pi-$ Bond formation
$(B) \,2p_x + 2p_x \to \sigma-$ Bond formation
$(C)\, 3d_{xy} + 3dp_{xy} \to \pi$ -Bond formation
$(D)\, 2s + 2p_y \to \pi-$ Bond formation
$(E)\, 3d_{xy} + 3d_{xy} \to \delta -$ Bond formation
$(F)\, 2p_s + 2p_s \to \sigma-$ Bond formation
$(1) Li < Be < B < C (IE_1)$
$(2) Li < Na < K < Rb < Cs$ (Reducing power in gaseous state)
$(3) Li^+ < Na^+ < K^+ < Rb^+ < Cs^+$ (Ionic mobility in aqueous solution)
$(4) S > Se > Te > O [EA]$
$[Image]$
the number of $sp ^{2}$ hybridised carbon (s) in compound ' $X$ ' is $.....$
