MCQ
Correct order for reaction with alcoholic $KOH$


- ✓$a > c > b > d $
- B$a > b > c > d$
- C$d > b > c > a$
- D$a > d > b > c$

$3^{\circ}>2^{\circ}>1^{\circ}$
The order of leaving group in $E 2$ elimination reaction is shown below :
$R - I > R - Br > R - Cl$
Therefore, the correct order for reaction with alcoholic $KOH$ is as follows :
$a > c > b > d$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$(a)$ $N,N-$ Dimethylaniline
$(b)$ $2,4 -$ Dimethylaniline
$(c)$ $N -$ methy $l-o-$ methylaniline
$(d)$ $p -$ Methylbenzylamine
