MCQ
Correct order is
- ✓$F > Cl > Br > I$ $(E.A.)$
- B$F_2 > Cl_2 > Br_2 > I_2$ (bond dissociation energy)
- C$F_2 > Cl_2 > Br_2 > I_2$ (oxidising power)
- D$F^-> Cl^-> Br^-> I^-$ (reducing power)
✓
Answer
Correct option: A.
$F > Cl > Br > I$ $(E.A.)$
a
$X = CH_4, Y = NaH, Z = HBr$
$X = CH_4, Y = NaH, Z = HBr$
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