MCQ
Correct order is
- A$Mn < Cr > Zn\,(IP)$
- B$La > Sc < Zn$ (size)
- ✓$F > P < N\, (IP)$
- D$Cl < F > Br\, (EA)$
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$CH \equiv CH\xrightarrow[{(excess)}]{{NaN{H_2}/liq.N{H_3}}}A\xrightarrow{{2C{H_3} - I}}B\xrightarrow[{quinolene}]{{{H_2}/Pd - BaS{O_4}}}C$
$C\xrightarrow[{quinolene}]{{{H_2}/Pd - BaS{O_4}}}\xrightarrow[{liq.\,N{H_3}}]{{NaN{H_2}}}D$
$\mathop {C{H_2} = C{H_2}}\limits_{(I)} $ $\mathop {C{H_3} - CH = C{H_2}}\limits_{(II)} $ (figure) $\mathop {C{H_2} = CH - Cl}\limits_{(IV)} $