MCQ
Correct order of atomic Radii (Metallic radii)
  • A
    $Mn\, >\, Cr$
  • B
    $Cu\, <\, Zn$
  • Both $(A)$ and $(B)$
  • D
    $Cr\, >\, Mn$

Answer

Correct option: C.
Both $(A)$ and $(B)$
c
The value is second IE generally increases towards the right in period, however $Cr ^{+}$has $3 d^5$ configuration which is extra-stable. Hence $2^{\text {nd }} IE$ of $Cr$ is more than that of Mn. Thus correct order of $2^{\text {nd }}$ IE is $C r>M n>V>T i$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free